2018-10-10 22:03:03 +00:00
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---
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id: 587d8253367417b2b2512c6c
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2020-12-16 07:37:30 +00:00
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title: 在两个集上执行联合
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2018-10-10 22:03:03 +00:00
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challengeType: 1
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videoUrl: ''
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---
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2020-12-16 07:37:30 +00:00
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# --description--
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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在本练习中,我们将对两组数据执行联合。我们将在我们的`Set`数据结构上创建一个名为`union` 。此方法应将另一个`Set`作为参数,并返回两个集合的`union`集,不包括任何重复值。例如,如果`setA = ['a','b','c']`和`setB = ['a','b','d','e']` ,则setA和setB的并集为: `setA.union(setB) = ['a', 'b', 'c', 'd', 'e']` 。
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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# --hints--
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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你的`Set`类应该有一个`union`方法。
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2018-10-10 22:03:03 +00:00
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```js
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2020-12-16 07:37:30 +00:00
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assert(
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(function () {
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var test = new Set();
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return typeof test.union === 'function';
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})()
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);
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2018-10-10 22:03:03 +00:00
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```
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2020-12-16 07:37:30 +00:00
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收回了适当的收藏
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2018-10-10 22:03:03 +00:00
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```js
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2020-12-16 07:37:30 +00:00
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assert(
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(function () {
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var setA = new Set();
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var setB = new Set();
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setA.add('a');
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setA.add('b');
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setA.add('c');
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setB.add('c');
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setB.add('d');
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var unionSetAB = setA.union(setB);
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var final = unionSetAB.values();
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return (
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final.indexOf('a') !== -1 &&
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final.indexOf('b') !== -1 &&
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final.indexOf('c') !== -1 &&
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final.indexOf('d') !== -1 &&
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final.length === 4
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);
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})()
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);
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2018-10-10 22:03:03 +00:00
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```
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2020-08-13 15:24:35 +00:00
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2020-12-16 07:37:30 +00:00
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# --solutions--
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