2018-10-10 22:03:03 +00:00
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---
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id: 5900f4291000cf542c50ff3b
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2020-12-16 07:37:30 +00:00
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title: 问题188：数字的过度扩展
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2018-10-10 22:03:03 +00:00
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challengeType: 5
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videoUrl: ''
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---
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2020-12-16 07:37:30 +00:00
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# --description--
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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由↑^ b或ba表示的正整数b的数字a的过度增强或分解通过以下方式递归地定义：a↑↑1 = a，a↑↑（k + 1）= a（a↑↑k ）。
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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因此我们有例如3↑↑2 = 33 = 27，因此3↑↑3 = 327 = 7625597484987和3↑↑4大致是103.6383346400240996 \* 10 ^ 12。查找1777↑↑1855的最后8位数字。
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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# --hints--
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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`euler188()`应该返回95962097。
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2018-10-10 22:03:03 +00:00
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```js
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2020-12-16 07:37:30 +00:00
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assert.strictEqual(euler188(), 95962097);
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2018-10-10 22:03:03 +00:00
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```
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2020-12-16 07:37:30 +00:00
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# --solutions--
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2020-08-13 15:24:35 +00:00
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