freeCodeCamp/curriculum/challenges/chinese/02-javascript-algorithms-an.../basic-javascript/compound-assignment-with-au...

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---
id: 56533eb9ac21ba0edf2244b0
title: 复合赋值之 -=
challengeType: 1
videoUrl: 'https://scrimba.com/c/c2Qv7AV'
forumTopicId: 16660
dashedName: compound-assignment-with-augmented-subtraction
---
# --description--
`+=` 操作符类似,`-=` 操作符用来对一个变量进行减法赋值操作。
`myVar = myVar - 5;`
变量 `myVar` 等于自身减去 `5` 的值。 也可以写成这种形式:
`myVar -= 5;`
# --instructions--
使用 `-=` 操作符对 `a``b` 和 `c` 实现相减赋值。
# --hints--
`a` 应该等于 `5`
```js
assert(a === 5);
```
`b` 应该等于 `-6`
```js
assert(b === -6);
```
`c` 应该等于 `2`
```js
assert(c === 2);
```
应该对每个变量使用 `-=` 操作符。
```js
assert(code.match(/-=/g).length === 3);
```
不要修改注释上面的代码。
```js
assert(
/var a = 11;/.test(code) && /var b = 9;/.test(code) && /var c = 3;/.test(code)
);
```
# --seed--
## --after-user-code--
```js
(function(a,b,c){ return "a = " + a + ", b = " + b + ", c = " + c; })(a,b,c);
```
## --seed-contents--
```js
var a = 11;
var b = 9;
var c = 3;
// Only change code below this line
a = a - 6;
b = b - 15;
c = c - 1;
```
# --solutions--
```js
var a = 11;
var b = 9;
var c = 3;
a -= 6;
b -= 15;
c -= 1;
```