freeCodeCamp/guide/chinese/tools/calculators/matrix-calculator/index.md

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---
title: Matrix Calculator
localeTitle: 矩阵计算器
---
## 矩阵计算器
矩阵计算器用于执行加法,减法或乘法。 另外,它可以执行特定于矩阵的操作,例如矩阵转置,反转或定义矩阵的等级。
Matrix由行和列nxm构建。在矩阵上完成的操作通常会对矩阵的维度施加一些限制。
##### 加成:
通过添加两个**相同**尺寸的矩阵的值来完成添加。 结果是一个与原始数组尺寸相同的数组。
```javascript
// matrices a and b are represented by an array of arrays (rows of columns)
function addMatrices(a, b) {
// we might want to add here constraints for the same dimensions
if (!Array.isArray(a) || !Array.isArray(a[0]) || !Array.isArray(b) || !Array.isArray(b[0])) {
throw new Error('a, b or it\'s children is not an array');
}
const result = [];
for (let i = 0; i < a.length; i++) {
result[i] = [];
for (let j = 0; j < a[i].length; j++) {
result[i][j] = a[i][j] + b[i][j];
}
}
return result;
}
```
##### 减法:
通过减去**相同**维度的两个矩阵的值来完成减法。 结果是一个与原始数组尺寸相同的数组。
```javascript
// matrices a and b are represented by an array of arrays (rows of columns)
function subtractMatrices(a, b) {
// we might want to add here constraints for the same dimensions
if (!Array.isArray(a) || !Array.isArray(a[0]) || !Array.isArray(b) || !Array.isArray(b[0])) {
throw new Error('a, b or it\'s children is not an array');
}
const result = [];
for (let i = 0; i < a.length; i++) {
result[i] = [];
for (let j = 0; j < a[i].length; j++) {
result[i][j] = a[i][j] - b[i][j];
}
}
return result;
}
```
##### 乘法:
乘法可以通过将矩阵乘以标量或乘以矩阵来完成。 如果我们乘以两个矩阵,只有当左矩阵中的列数等于右矩阵中的行数时才能进行。
```javascript
// matrices a and b are represented by an array of arrays (rows of columns)
function multiplyMatrices(a, b) {
// we might want to add here constraints for the dimensions
//let's assume that b has to be either a scalar or an array
if (!Array.isArray(a) || !Array.isArray(a[0]) || ((!Array.isArray(b) || !Array.isArray(b[0])) && isNaN(b))) {
throw new Error('a, b or it\'s children is not an array');
}
if (!isNaN(b)) {
for (let i = 0; i < a.length; i++) {
for (let j = 0; j < a[i].length; j++) {
a[i][j] = a[i][j] * b;
}
}
return a;
}
const result = [];
for (let i = 0; i < a.length; i++) {
result[i] = [];
for (let j = 0; j < a[i].length; j++) {
let sum = 0;
for (let k = 0; k < b[i].length; k++) {
sum += a[i][k] * b[k][j];
}
result[i][j] = sum;
}
}
return result;
}
```
#### 更多信息:
https://en.wikipedia.org/wiki/Matrix\_(mathematics