freeCodeCamp/guide/english/certifications/javascript-algorithms-and-d.../regular-expressions/reuse-patterns-using-captur.../index.md

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2018-10-12 19:37:13 +00:00
---
title: Reuse Patterns Using Capture Groups
---
## Reuse Patterns Using Capture Group
## Hint 1:
Given code below:
```javascript
let testString = "test test test ";
let reRegex =/(test)\s\1/;
let result = reRegex.test(testString);
```
`result` will match only `test test` because `\1` in this example stands for the same text as most recently matched by the 1st capturing group `(test)`.
If we were to lierally translate the regex, it would look something like this:
```js
let re = /(test)\s\1;
let literalRe = /test\stest;
```
Both `rea` and `literalRe` would match the same thing.
## Hint 2:
Given the code below:
```javascript
let testString = "test test test ";
let reRegex =/(test)(\s)\1\2\1/;
let result = reRegex.test(testString);
```
will match whole `test test test` because:
`\1` repeats (test)
`\2` repeats (\s)
## Hint 3:
The code below:
```javascript
let testString = "test test test test test test";
let reRegex =/(test)(\s)\1\2\1/g;
let result = reRegex.test(testString);
```
because we used `\g`, our Regex doesn't return after first full match (`test test test`) and matched all repetitions.
## Spoiler Alert - Solution Ahead!
## Solution:
```javascript
let repeatNum = "42 42 42";
let reRegex = /^(\d+)\s\1\s\1$/;
let result = reRegex.test(repeatNum);
```