2018-10-10 22:03:03 +00:00
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---
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id: 5900f3f21000cf542c50ff04
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2020-12-16 07:37:30 +00:00
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title: 问题133:重新计算非因素
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2018-10-10 22:03:03 +00:00
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challengeType: 5
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videoUrl: ''
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2021-01-13 02:31:00 +00:00
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dashedName: problem-133-repunit-nonfactors
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2018-10-10 22:03:03 +00:00
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---
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2020-12-16 07:37:30 +00:00
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# --description--
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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完全由1组成的数字称为repunit。我们将R(k)定义为长度k的重新定位;例如,R(6)= 111111.让我们考虑R(10n)形式的重新组合。虽然R(10),R(100)或R(1000)不能被17整除,但R(10000)可被17整除。但是没有n的值,R(10n)将除以19。事实上,值得注意的是,11,17,41和73是低于100的唯一四个素数,可以是R(10n)的因子。求出十万以下所有素数的总和,这些素数永远不会是R(10n)的因子。
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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# --hints--
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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`euler133()`应返回453647705。
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2018-10-10 22:03:03 +00:00
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```js
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2020-12-16 07:37:30 +00:00
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assert.strictEqual(euler133(), 453647705);
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2018-10-10 22:03:03 +00:00
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```
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2021-01-13 02:31:00 +00:00
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# --seed--
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## --seed-contents--
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```js
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function euler133() {
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return true;
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}
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euler133();
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```
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2020-12-16 07:37:30 +00:00
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# --solutions--
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2020-08-13 15:24:35 +00:00
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2021-01-13 02:31:00 +00:00
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```js
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// solution required
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```
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