freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/project-euler/problem-16-power-digit-sum.md

---
id: 5900f37d1000cf542c50fe8f
title: 问题16：电源数字总和
challengeType: 5
videoUrl: ''
dashedName: problem-16-power-digit-sum
---

# --description--

2 <sup>15<!-- sup-->= 32768，其位数之和为3 + 2 + 7 + 6 + 8 = 26。 2 <sup><code>指数<!-- code--><!-- sup-->的数字总和是多少？</code></sup></sup>

# --hints--

`powerDigitSum(15)`应该返回26。

```js
assert.strictEqual(powerDigitSum(15), 26);
```

`powerDigitSum(128)`应该返回166。

```js
assert.strictEqual(powerDigitSum(128), 166);
```

`powerDigitSum(1000)`应返回1366。

```js
assert.strictEqual(powerDigitSum(1000), 1366);
```

# --seed--

## --seed-contents--

```js
function powerDigitSum(exponent) {

  return true;
}

powerDigitSum(15);
```

# --solutions--

```js
function powerDigitSum(exponent) {
  const bigNum = [1];
  let sum = 0;

  for (let i = 1; i <= exponent; i++) {
    let count = bigNum.length + 1;
    let overflow = 0;
    for (let j = 0; j < count; j++) {
      let digit = bigNum[j] || 0;
      digit = 2 * digit + overflow;

      if (digit > 9) {
        digit -= 10;
        overflow = 1;
      } else {
        overflow = 0;
      }

      bigNum[j] = digit;
    }
  }

  bigNum.forEach(function(num) {
    return sum += num;
  });

  return sum;
}
```