2018-10-10 22:03:03 +00:00
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---
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id: 5900f4151000cf542c50ff27
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2020-12-16 07:37:30 +00:00
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title: 问题168:数字轮换
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2018-10-10 22:03:03 +00:00
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challengeType: 5
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videoUrl: ''
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2021-01-13 02:31:00 +00:00
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dashedName: problem-168-number-rotations
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2018-10-10 22:03:03 +00:00
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---
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2020-12-16 07:37:30 +00:00
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# --description--
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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考虑数字142857.我们可以通过将最后一个数字(7)移动到它的前面来右旋这个数字,给我们714285.可以验证714285 = 5×142857。这证明了142857的一个不寻常的属性:它是右旋的除数。找到具有此属性的所有整数n,10 <n <10100之和的最后5位数。
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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# --hints--
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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`euler168()`应返回`euler168()` 。
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2018-10-10 22:03:03 +00:00
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```js
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2020-12-16 07:37:30 +00:00
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assert.strictEqual(euler168(), 59206);
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2018-10-10 22:03:03 +00:00
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```
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2021-01-13 02:31:00 +00:00
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# --seed--
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## --seed-contents--
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```js
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function euler168() {
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return true;
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}
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euler168();
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```
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2020-12-16 07:37:30 +00:00
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# --solutions--
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2020-08-13 15:24:35 +00:00
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2021-01-13 02:31:00 +00:00
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```js
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// solution required
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```
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