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---
id: 5900f3b21000cf542c50fec5
title: 'Problem 70: Totient permutation'
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challengeType: 5
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forumTopicId: 302183
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dashedName: problem-70-totient-permutation
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---
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# --description--
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Euler's Totient function, φ(`n`) \[sometimes called the phi function], is used to determine the number of positive numbers less than or equal to `n` which are relatively prime to `n` . For example, as 1, 2, 4, 5, 7, and 8, are all less than nine and relatively prime to nine, φ(9)=6. The number 1 is considered to be relatively prime to every positive number, so φ(1)=1.
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Interestingly, φ(87109)=79180, and it can be seen that 87109 is a permutation of 79180.
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Find the value of `n` , 1 < `n` < 10< sup > 7</ sup > , for which φ(`n`) is a permutation of `n` and the ratio `n` /φ(`n`) produces a minimum.
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# --hints--
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`totientPermutation()` should return a number.
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```js
assert(typeof totientPermutation() === 'number');
```
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`totientPermutation()` should return 8319823.
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```js
assert.strictEqual(totientPermutation(), 8319823);
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```
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# --seed--
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## --seed-contents--
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```js
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function totientPermutation() {
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return true;
}
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totientPermutation();
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```
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# --solutions--
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```js
// solution required
```