freeCodeCamp/curriculum/challenges/chinese/08-coding-interview-prep/data-structures/perform-a-union-on-two-sets...

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---
id: 587d8253367417b2b2512c6c
title: Perform a Union on Two Sets
challengeType: 1
videoUrl: ''
localeTitle: 在两个集上执行联合
---
## Description
<section id="description">在本练习中,我们将对两组数据执行联合。我们将在我们的<code>Set</code>数据结构上创建一个名为<code>union</code> 。此方法应将另一个<code>Set</code>作为参数,并返回两个集合的<code>union</code>集,不包括任何重复值。例如,如果<code>setA = [&#39;a&#39;,&#39;b&#39;,&#39;c&#39;]</code><code>setB = [&#39;a&#39;,&#39;b&#39;,&#39;d&#39;,&#39;e&#39;]</code> 则setA和setB的并集为 <code>setA.union(setB) = [&#39;a&#39;, &#39;b&#39;, &#39;c&#39;, &#39;d&#39;, &#39;e&#39;]</code></section>
## Instructions
<section id="instructions">
</section>
## Tests
<section id='tests'>
```yml
tests:
- text: 你的<code>Set</code>类应该有一个<code>union</code>方法。
testString: 'assert((function(){var test = new Set(); return (typeof test.union === "function")})(), "Your <code>Set</code> class should have a <code>union</code> method.");'
- text: 收回了适当的收藏
testString: 'assert((function(){var setA = new Set(); var setB = new Set(); setA.add("a"); setA.add("b"); setA.add("c"); setB.add("c"); setB.add("d"); var unionSetAB = setA.union(setB); var final = unionSetAB.values(); return (final.indexOf("a") !== -1 && final.indexOf("b") !== -1 && final.indexOf("c") !== -1 && final.indexOf("d") !== -1 && final.length === 4)})(), "The proper collection was returned");'
```
</section>
## Challenge Seed
<section id='challengeSeed'>
<div id='js-seed'>
```js
function Set() {
// the var collection will hold the set
var collection = [];
// this method will check for the presence of an element and return true or false
this.has = function(element) {
return (collection.indexOf(element) !== -1);
};
// this method will return all the values in the set
this.values = function() {
return collection;
};
// this method will add an element to the set
this.add = function(element) {
if(!this.has(element)){
collection.push(element);
return true;
}
return false;
};
// this method will remove an element from a set
this.remove = function(element) {
if(this.has(element)){
var index = collection.indexOf(element);
collection.splice(index,1);
return true;
}
return false;
};
// this method will return the size of the set
this.size = function() {
return collection.length;
};
// change code below this line
// change code above this line
}
```
</div>
</section>
## Solution
<section id='solution'>
```js
// solution required
```
</section>