freeCodeCamp/curriculum/challenges/japanese/10-coding-interview-prep/project-euler/problem-157-solving-the-dio...

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---
id: 5900f4091000cf542c50ff1c
title: '問題 157: ディオファントス方程式を解く'
challengeType: 5
forumTopicId: 301788
dashedName: problem-157-solving-the-diophantine-equation
---
# --description--
$a$, $b$, $p$, $n$ を正の整数とし、$a ≤ b$ を満たすディオファントス方程式 $\frac{1}{a} + \frac{1}{b} = \frac{p}{{10}^n}$ について考えます。
$n = 1$ のとき、この方程式は次の 20 個の解を持ちます。
$$\begin{array}{lllll} \frac{1}{1} + \frac{1}{1} = \frac{20}{10} & \frac{1}{1} + \frac{1}{2} = \frac{15}{10} & \frac{1}{1} + \frac{1}{5} = \frac{12}{10} & \frac{1}{1} + \frac{1}{10} = \frac{11}{10} & \frac{1}{2} + \frac{1}{2} = \frac{10}{10} \\\\
\frac{1}{2} + \frac{1}{5} = \frac{7}{10} & \frac{1}{2} + \frac{1}{10} = \frac{6}{10} & \frac{1}{3} + \frac{1}{6} = \frac{5}{10} & \frac{1}{3} + \frac{1}{15} = \frac{4}{10} & \frac{1}{4} + \frac{1}{4} = \frac{5}{10} \\\\
\frac{1}{4} + \frac{1}{4} = \frac{5}{10} & \frac{1}{5} + \frac{1}{5} = \frac{4}{10} & \frac{1}{5} + \frac{1}{10} = \frac{3}{10} & \frac{1}{6} + \frac{1}{30} = \frac{2}{10} & \frac{1}{10} + \frac{1}{10} = \frac{2}{10} \\\\
\frac{1}{11} + \frac{1}{110} = \frac{1}{10} & \frac{1}{12} + \frac{1}{60} = \frac{1}{10} & \frac{1}{14} + \frac{1}{35} = \frac{1}{10} & \frac{1}{15} + \frac{1}{30} = \frac{1}{10} & \frac{1}{20} + \frac{1}{20} = \frac{1}{10} \end{array}$$
$1 ≤ n ≤ 9$ のとき、この方程式の解はいくつありますか。
# --hints--
`diophantineEquation()``53490` を返す必要があります。
```js
assert.strictEqual(diophantineEquation(), 53490);
```
# --seed--
## --seed-contents--
```js
function diophantineEquation() {
return true;
}
diophantineEquation();
```
# --solutions--
```js
// solution required
```