2019-05-06 11:31:26 +00:00
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---
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id: 587d7fb7367417b2b2512c0b
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2020-12-16 07:37:30 +00:00
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title: 使用model.find()搜索数据库
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2019-05-06 11:31:26 +00:00
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challengeType: 2
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2020-09-17 10:53:54 +00:00
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forumTopicId: 301543
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2019-05-06 11:31:26 +00:00
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---
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2020-12-16 07:37:30 +00:00
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# --description--
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2019-05-06 11:31:26 +00:00
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2020-12-16 07:37:30 +00:00
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使用 `Model.find() -> [Person]` 找出符合名字查询条件的所有人。
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2019-05-06 11:31:26 +00:00
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2020-12-16 07:37:30 +00:00
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`Model.find()` 接收一个查询 document(一个 JSON 对象)作为第一个参数,然后第二个参数是一个回调函数,它会返回由匹配到的数据组成的数组。这个方法支持很多搜索选项,详情请参阅文档。在这个挑战中,请使用 `personName` 作为搜索条件。
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2019-05-06 11:31:26 +00:00
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2020-12-16 07:37:30 +00:00
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# --hints--
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2019-05-06 11:31:26 +00:00
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2020-12-16 07:37:30 +00:00
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应成功地找到所有符合条件的数据
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2019-05-06 11:31:26 +00:00
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```js
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2020-12-16 07:37:30 +00:00
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(getUserInput) =>
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$.post(getUserInput('url') + '/_api/find-all-by-name', {
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name: 'r@nd0mN4m3',
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age: 24,
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favoriteFoods: ['pizza']
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}).then(
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(data) => {
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assert.isArray(data, 'the response should be an Array');
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assert.equal(
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data[0].name,
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'r@nd0mN4m3',
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'item.name is not what expected'
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);
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assert.equal(data[0].__v, 0, 'The item should be not previously edited');
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},
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(xhr) => {
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throw new Error(xhr.responseText);
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}
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);
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2019-05-06 11:31:26 +00:00
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```
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2020-08-13 15:24:35 +00:00
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2020-12-16 07:37:30 +00:00
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# --solutions--
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