18 lines
452 B
Markdown
18 lines
452 B
Markdown
|
---
|
|||
|
|
title: Find Characters with Lazy Matching
|
|||
|
|
localeTitle: 查找具有延迟匹配的字符
|
|||
|
|
---
|
|||
|
|
## 查找具有延迟匹配的字符
|
|||
|
|
|
|||
|
|
#### Challange：
|
|||
|
|
|
|||
|
|
修复regex `/<.*>/`以返回HTML标记`<h1>`而不是文本`<h1>Winter is coming</h1>` 。记住通配符。在正则表达式中匹配任何字符。
|
|||
|
|
|
|||
|
|
#### 解：
|
|||
|
|
|
|||
|
|
```js
|
|||
|
|
let text = "<h1>Winter is coming</h1>";
|
|||
|
|
let myRegex = /<h1>?/; // it's the answer!
|
|||
|
|
let result = text.match(myRegex);
|
|||
|
|
|
|||
|
|
```
|