2018-10-10 22:03:03 +00:00
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---
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id: 594ecc0d9a8cf816e3340187
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2020-12-16 07:37:30 +00:00
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title: 出租车号码
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2018-10-10 22:03:03 +00:00
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challengeType: 5
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videoUrl: ''
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---
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2020-12-16 07:37:30 +00:00
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# --description--
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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[出租车编号](<https://en.wikipedia.org/wiki/Hardy–Ramanujan number> "wp:Hardy-Ramanujan号码") (此处使用的定义)是一个正整数,可以用多种方式表示为两个正立方体的总和。第一个出租车编号是1729,即:1 <sup>3</sup> + 12 <sup>3</sup>和9 <sup>3</sup> + 10 <sup>3</sup> 。出租车号码也被称为:\*出租车号码\*出租车号码\*出租车号码\* Hardy-Ramanujan号码任务:编写一个返回最低N个出租车号码的函数。对于每个出租车编号,显示数字以及它的构成立方体。另请参阅:在线整数序列百科全书上的\[`http://oeis.org/A001235` A001235出租车编号]。 MathWorld上的[Hardy-Ramanujan数字](http://mathworld.wolfram.com/Hardy-RamanujanNumber.html) 。 MathWorld上的[出租车编号](http://mathworld.wolfram.com/TaxicabNumber.html) 。维基百科上的[出租车号码](https://en.wikipedia.org/wiki/Taxicab_number) 。
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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# --hints--
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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`taxicabNumbers`是一个功能。
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2018-10-10 22:03:03 +00:00
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```js
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2020-12-16 07:37:30 +00:00
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assert(typeof taxicabNumbers === 'function');
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```
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`taxicabNumbers`应该返回一个数组。
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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```js
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assert(typeof taxicabNumbers(2) === 'object');
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2018-10-10 22:03:03 +00:00
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```
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2020-12-16 07:37:30 +00:00
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`taxicabNumbers`应返回一组数字。
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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```js
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assert(typeof taxicabNumbers(100)[0] === 'number');
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```
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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`taxicabNumbers(4)`必须返回[1729,4104,13832,20683]。
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2018-10-10 22:03:03 +00:00
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```js
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2020-12-16 07:37:30 +00:00
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assert.deepEqual(taxicabNumbers(4), res4);
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2018-10-10 22:03:03 +00:00
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```
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2020-12-16 07:37:30 +00:00
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taxicabNumbers(25)应该返回[1729,4104,13832,20683,32832,39312,40033,46683,64232,65728,110656,110808,134379,149389,165464,171288,195841,216027,216125,262656,314696,320264 ,327763,373464,402597]
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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```js
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assert.deepEqual(taxicabNumbers(25), res25);
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```
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2018-10-10 22:03:03 +00:00
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2020-12-16 07:37:30 +00:00
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taxicabNumbers(39)由20 - 29得到的数字应为[314496,320264,327763,373464,402597,439101,443889,513000,513856]。
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2018-10-10 22:03:03 +00:00
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```js
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2020-12-16 07:37:30 +00:00
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assert.deepEqual(taxicabNumbers(39).slice(20, 29), res39From20To29);
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2018-10-10 22:03:03 +00:00
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```
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2020-08-13 15:24:35 +00:00
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2020-12-16 07:37:30 +00:00
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# --solutions--
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