freeCodeCamp/curriculum/challenges/italian/10-coding-interview-prep/project-euler/problem-63-powerful-digit-c...

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---
id: 5900f3ab1000cf542c50febe
title: 'Problem 63: Powerful digit counts'
challengeType: 5
forumTopicId: 302175
dashedName: problem-63-powerful-digit-counts
---
# --description--
The 5-digit number, 16807 = 7<sup>5</sup>, is also a fifth power. Similarly, the 9-digit number, 134217728 = 8<sup>9</sup>, is a ninth power.
Complete the function so that it returns how many positive integers are of length `n` and an `n`th power.
# --hints--
`powerfulDigitCounts(1)` should return a number.
```js
assert(typeof powerfulDigitCounts(1) === 'number');
```
`powerfulDigitCounts(1)` should return `9`.
```js
assert.strictEqual(powerfulDigitCounts(1), 9);
```
`powerfulDigitCounts(2)` should return `6`.
```js
assert.strictEqual(powerfulDigitCounts(2), 6);
```
`powerfulDigitCounts(3)` should return `5`.
```js
assert.strictEqual(powerfulDigitCounts(3), 5);
```
`powerfulDigitCounts(4)` should return `4`.
```js
assert.strictEqual(powerfulDigitCounts(4), 4);
```
`powerfulDigitCounts(5)` should return `3`.
```js
assert.strictEqual(powerfulDigitCounts(5), 3);
```
`powerfulDigitCounts(6)` should return `3`.
```js
assert.strictEqual(powerfulDigitCounts(6), 3);
```
`powerfulDigitCounts(7)` should return `2`.
```js
assert.strictEqual(powerfulDigitCounts(7), 2);
```
`powerfulDigitCounts(8)` should return `2`.
```js
assert.strictEqual(powerfulDigitCounts(8), 2);
```
`powerfulDigitCounts(10)` should return `2`.
```js
assert.strictEqual(powerfulDigitCounts(10), 2);
```
`powerfulDigitCounts(21)` should return `1`.
```js
assert.strictEqual(powerfulDigitCounts(21), 1);
```
# --seed--
## --seed-contents--
```js
function powerfulDigitCounts(n) {
return true;
}
powerfulDigitCounts(1);
```
# --solutions--
```js
function powerfulDigitCounts(n) {
function countDigits(num) {
let counter = 0;
while (num > 0) {
num = Math.floor(num / 10);
counter++;
}
return counter;
}
let numbersCount = 0;
let curNum = 1;
while (curNum < 10) {
let power = n;
if (power === countDigits(curNum ** power)) {
numbersCount++;
}
curNum++;
}
return numbersCount;
}
```