2018-10-10 22:03:03 +00:00
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---
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id: 5900f3ec1000cf542c50feff
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challengeType: 5
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videoUrl: ''
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2020-10-01 15:54:21 +00:00
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title: 问题128:六边形瓷砖差异
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2018-10-10 22:03:03 +00:00
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---
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## Description
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<section id="description">编号为1的六边形瓷砖由六个六边形瓷砖环围绕,从“12点钟”开始,并以逆时针方向对瓷砖2至7进行编号。新环以相同的方式添加,下一个环编号为8至19,20至37,38至61,依此类推。下图显示了前三个环。 <p>通过找到tile n与其六个邻居中的每一个之间的差异,我们将PD(n)定义为那些作为素数的差异的数量。例如,在瓦片8周围顺时针工作,差异是12,29,11,6,1和13.因此PD(8)= 3.以相同的方式,瓦片17周围的差异是1,17,16,1 ,11和10,因此PD(17)= 2.可以证明PD(n)的最大值是3.如果PD(n)= 3的所有瓦片按升序列出以形成一个序列,第10个瓦片将是271.按此顺序找到第2000个瓦片。 </p></section>
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## Instructions
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<section id="instructions">
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</section>
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## Tests
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<section id='tests'>
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```yml
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tests:
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- text: <code>euler128()</code>应该返回14516824220。
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2020-02-17 16:40:55 +00:00
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testString: assert.strictEqual(euler128(), 14516824220);
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2018-10-10 22:03:03 +00:00
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```
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</section>
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## Challenge Seed
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<section id='challengeSeed'>
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<div id='js-seed'>
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```js
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function euler128() {
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// Good luck!
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return true;
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}
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euler128();
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```
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</div>
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</section>
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## Solution
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<section id='solution'>
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```js
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// solution required
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```
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2020-08-13 15:24:35 +00:00
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/section>
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