freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/project-euler/problem-29-distinct-powers.md

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---
id: 5900f3891000cf542c50fe9c
challengeType: 5
videoUrl: ''
2020-10-01 15:54:21 +00:00
title: 问题29不同的权力
---
## Description
<section id="description">
考虑2≤a≤5和2≤b≤5的ab的所有整数组合
22 = 4、23 = 8、24 = 16、25 = 32
32 = 9、33 = 27、34 = 81、35 = 243
42 = 16、43 = 64、44 = 256、45 = 1024
52 = 25、53 = 125、54 = 625、55 = 3125
如果然后按数字顺序放置它们并删除所有重复项则会得到以下15个不同术语的序列
48916252732648112524325662510243125
对于2≤a≤n和2≤b≤n由ab生成的序列中有多少个不同的项
</section>
## Instructions
<section id="instructions">
</section>
## Tests
<section id='tests'>
```yml
tests:
- text: <code>distinctPowers(15)</code>应该返回177。
testString: assert.strictEqual(distinctPowers(15), 177);
- text: <code>distinctPowers(20)</code>应该返回324。
testString: assert.strictEqual(distinctPowers(20), 324);
- text: <code>distinctPowers(25)</code>应该返回519。
testString: assert.strictEqual(distinctPowers(25), 519);
- text: <code>distinctPowers(30)</code>应该返回755。
testString: assert.strictEqual(distinctPowers(30), 755);
```
</section>
## Challenge Seed
<section id='challengeSeed'>
<div id='js-seed'>
```js
function distinctPowers(n) {
// Good luck!
return n;
}
distinctPowers(30);
```
</div>
</section>
## Solution
<section id='solution'>
```js
// solution required
```
/section>