28 lines
898 B
Markdown
28 lines
898 B
Markdown
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---
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title: Multiples of 3 and 5
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---
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## Problem 1: Multiples of 3 and 5
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### Method:
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- We can find if a number is divisble by another number with the help of `%` modulo operator.
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- `num1 % num2` returns `0` if there's no remainder while doing `num1/num2`.
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- Starting from `i = 3` because that's the first number that's divisble by 3 or 5, we loop through till the `number` provided.
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- If the number is divisible either by 3 or 5, we add that to the variable `sum` and finally return it.
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### Solution:
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```js
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function multiplesOf3and5(number) {
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let sum = 0, i = 3;
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while (i < number){
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if (i % 3 == 0 || i % 5 == 0) sum += i;
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i++;
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}
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return sum;
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}
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```
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- [Run Code](https://repl.it/@ezioda004/Project-Euler-Problem-1-Multiples-of-3-and-5)
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### Reference:
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- [Modulo operator](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Arithmetic_Operators#Remainder_())
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