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---
id: 5900f3b31000cf542c50fec6
title: 'Problem 71: Ordered fractions'
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challengeType: 5
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forumTopicId: 302184
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dashedName: problem-71-ordered-fractions
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---
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# --description--
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Consider the fraction, `n` /`d`, where `n` and `d` are positive integers. If `n` < `d` and HCF(`n`,`d`)=1, it is called a reduced proper fraction.
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If we list the set of reduced proper fractions for `d` ≤ 8 in ascending order of size, we get:
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< div style = 'text-align: center;' > 1/8, 1/7, 1/6, 1/5, 1/4, 2/7, 1/3, 3/8, < strong > 2/5< / strong > , 3/7, 1/2, 4/7, 3/5, 5/8, 2/3, 5/7, 3/4, 4/5, 5/6, 6/7, 7/8< / div >
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It can be seen that 2/5 is the fraction immediately to the left of 3/7.
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By listing the set of reduced proper fractions for `d` ≤ 1,000,000 in ascending order of size, find the numerator of the fraction immediately to the left of 3/7.
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# --hints--
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`orderedFractions()` should return a number.
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```js
assert(typeof orderedFractions() === 'number');
```
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`orderedFractions()` should return 428570.
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```js
assert.strictEqual(orderedFractions(), 428570);
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```
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# --seed--
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## --seed-contents--
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```js
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function orderedFractions() {
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return true;
}
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orderedFractions();
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```
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# --solutions--
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```js
// solution required
```