80 lines
1.1 KiB
Markdown
80 lines
1.1 KiB
Markdown
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---
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id: 5a23c84252665b21eecc7ede
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title: Leap year
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challengeType: 5
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forumTopicId: 302300
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dashedName: leap-year
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---
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# --description--
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Determine whether a given year is a leap year in the Gregorian calendar.
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# --hints--
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`isLeapYear` should be a function.
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```js
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assert(typeof isLeapYear == 'function');
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```
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`isLeapYear()` should return a boolean.
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```js
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assert(typeof isLeapYear(2018) == 'boolean');
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```
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`isLeapYear(2018)` should return `false`.
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```js
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assert.equal(isLeapYear(2018), false);
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```
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`isLeapYear(2016)` should return `true`.
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```js
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assert.equal(isLeapYear(2016), true);
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```
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`isLeapYear(2000)` should return `true`.
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```js
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assert.equal(isLeapYear(2000), true);
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```
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`isLeapYear(1900)` should return `false`.
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```js
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assert.equal(isLeapYear(1900), false);
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```
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`isLeapYear(1996)` should return `true`.
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```js
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assert.equal(isLeapYear(1996), true);
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```
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`isLeapYear(1800)` should return `false`.
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```js
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assert.equal(isLeapYear(1800), false);
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```
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# --seed--
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## --seed-contents--
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```js
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function isLeapYear(year) {
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}
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```
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# --solutions--
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```js
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function isLeapYear(year) {
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return year % 100 === 0 ? year % 400 === 0 : year % 4 === 0;
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}
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```
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