freeCodeCamp/curriculum/challenges/portuguese/02-javascript-algorithms-an.../basic-javascript/compound-assignment-with-au...

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---
id: 56533eb9ac21ba0edf2244b0
title: Compound Assignment With Augmented Subtraction
challengeType: 1
videoUrl: 'https://scrimba.com/c/c2Qv7AV'
forumTopicId: 16660
dashedName: compound-assignment-with-augmented-subtraction
---
# --description--
Like the `+=` operator, `-=` subtracts a number from a variable.
```js
myVar = myVar - 5;
```
will subtract `5` from `myVar`. This can be rewritten as:
```js
myVar -= 5;
```
# --instructions--
Convert the assignments for `a`, `b`, and `c` to use the `-=` operator.
# --hints--
`a` should equal `5`.
```js
assert(a === 5);
```
`b` should equal `-6`.
```js
assert(b === -6);
```
`c` should equal `2`.
```js
assert(c === 2);
```
You should use the `-=` operator for each variable.
```js
assert(code.match(/-=/g).length === 3);
```
You should not modify the code above the specified comment.
```js
assert(
/var a = 11;/.test(code) && /var b = 9;/.test(code) && /var c = 3;/.test(code)
);
```
# --seed--
## --after-user-code--
```js
(function(a,b,c){ return "a = " + a + ", b = " + b + ", c = " + c; })(a,b,c);
```
## --seed-contents--
```js
var a = 11;
var b = 9;
var c = 3;
// Only change code below this line
a = a - 6;
b = b - 15;
c = c - 1;
```
# --solutions--
```js
var a = 11;
var b = 9;
var c = 3;
a -= 6;
b -= 15;
c -= 1;
```