67 lines
1.7 KiB
Markdown
67 lines
1.7 KiB
Markdown
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---
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title: Accumulator factory
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id: 594810f028c0303b75339ace
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challengeType: 5
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videoUrl: ''
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localeTitle: 蓄能器工厂
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---
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## Description
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<section id="description"><p>创建一个带有单个（数字）参数的函数，并返回另一个作为累加器的函数。返回的累加器函数又接受一个数字参数，并返回到目前为止传递给该累加器的所有数值的总和（包括创建累加器时传递的初始值）。 </p><p>规则： </p><p>不要使用全局变量。 </p><p>暗示： </p><p>闭包可以保存外部状态。 </p></section>
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## Instructions
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<section id="instructions">
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</section>
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## Tests
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<section id='tests'>
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```yml
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tests:
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- text: <code>accumulator</code>是一个功能。
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testString: 'assert(typeof accumulator === "function", "<code>accumulator</code> is a function.");'
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- text: <code>accumulator(0)</code>应该返回一个函数。
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testString: 'assert(typeof accumulator(0) === "function", "<code>accumulator(0)</code> should return a function.");'
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- text: <code>accumulator(0)(2)</code>应该返回一个数字。
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testString: 'assert(typeof accumulator(0)(2) === "number", "<code>accumulator(0)(2)</code> should return a number.");'
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- text: '传递值3，-4,1.5和5应返回5.5。'
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testString: 'assert(testFn(5) === 5.5, "Passing in the values 3, -4, 1.5, and 5 should return 5.5.");'
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```
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</section>
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## Challenge Seed
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<section id='challengeSeed'>
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<div id='js-seed'>
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```js
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function accumulator (sum) {
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// Good luck!
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}
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```
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</div>
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### After Test
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<div id='js-teardown'>
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```js
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console.info('after the test');
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```
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</div>
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</section>
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## Solution
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<section id='solution'>
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```js
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// solution required
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```
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</section>
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