104 lines
4.0 KiB
Markdown
104 lines
4.0 KiB
Markdown
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---
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id: 587d8253367417b2b2512c6d
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title: Perform an Intersection on Two Sets of Data
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localeTitle: Realizar una intersección en dos conjuntos de datos
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challengeType: 1
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---
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## Description
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<section id='description'>
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En este ejercicio vamos a realizar una intersección en 2 conjuntos de datos. Crearemos un método en nuestra estructura de datos del <code>Set</code> llamada <code>intersection</code> . Una intersección de conjuntos representa todos los valores que son comunes a dos o más conjuntos. Este método debe tomar otro <code>Set</code> como argumento y devolver la <code>intersection</code> de los dos conjuntos.
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Por ejemplo, si <code>setA = ['a','b','c']</code> y <code>setB = ['a','b','d','e']</code> , entonces la intersección de setA y setB es: <code>setA.intersection(setB) = ['a', 'b']</code> .
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</section>
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## Instructions
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<section id='instructions'>
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</section>
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## Tests
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<section id='tests'>
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```yml
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tests:
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- text: Tu clase <code>Set</code> debería tener un método de <code>intersection</code> .
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testString: 'assert(function(){var test = new Set(); return (typeof test.intersection === "function")}, "Your <code>Set</code> class should have a <code>intersection</code> method.");'
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- text: Se devolvió la colección adecuada.
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testString: 'assert(function(){ var setA = new Set(); var setB = new Set(); setA.add("a"); setA.add("b"); setA.add("c"); setB.add("c"); setB.add("d"); var intersectionSetAB = setA.intersection(setB); return (intersectionSetAB.size() === 1 && intersectionSetAB.values()[0] === "c")}, "The proper collection was returned");'
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```
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</section>
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## Challenge Seed
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<section id='challengeSeed'>
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<div id='js-seed'>
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```js
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function Set() {
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// the var collection will hold the set
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var collection = [];
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// this method will check for the presence of an element and return true or false
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this.has = function(element) {
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return (collection.indexOf(element) !== -1);
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};
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// this method will return all the values in the set
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this.values = function() {
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return collection;
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};
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// this method will add an element to the set
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this.add = function(element) {
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if(!this.has(element)){
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collection.push(element);
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return true;
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}
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return false;
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};
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// this method will remove an element from a set
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this.remove = function(element) {
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if(this.has(element)){
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var index = collection.indexOf(element);
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collection.splice(index,1);
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return true;
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}
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return false;
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};
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// this method will return the size of the collection
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this.size = function() {
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return collection.length;
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};
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// this method will return the union of two sets
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this.union = function(otherSet) {
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var unionSet = new Set();
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var firstSet = this.values();
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var secondSet = otherSet.values();
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firstSet.forEach(function(e){
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unionSet.add(e);
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});
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secondSet.forEach(function(e){
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unionSet.add(e);
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});
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return unionSet;
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};
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// change code below this line
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// change code above this line
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}
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```
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</div>
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</section>
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## Solution
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<section id='solution'>
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```js
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function Set() {var collection = []; this.has = function(e){return(collection.indexOf(e) !== -1);};this.values = function() {return collection;};this.add = function(element) {if (!this.has(element)) {collection.push(element);return true;} else {return false;}};this.remove = function(element) {if(this.has(element)) {var i = collection.indexOf(element);collection.splice(i, 1);return true;}return false;};this.size = function() {return collection.length;};this.union = function(set) {var u = new Set();var c = this.values();var s = set.values();c.forEach(function(element){u.add(element);});s.forEach(function(element){u.add(element);});return u;};this.intersection = function(set) {var i = new Set();var c = this.values();c.forEach(function(element){if(s.has(element)) i.add(element);});};}
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```
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</section>
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