2021-06-15 07:49:18 +00:00
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---
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id: 5900f40d1000cf542c50ff1f
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2022-02-28 07:59:21 +00:00
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title: 'Problema 160: Cifre finali dei fattoriali'
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2021-06-15 07:49:18 +00:00
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challengeType: 5
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forumTopicId: 301794
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dashedName: problem-160-factorial-trailing-digits
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---
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# --description--
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2022-02-28 07:59:21 +00:00
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Per ogni $N$, $f(N)$ rappresenti le ultime cinque cifre prima degli zero finali in $N!$.
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2021-06-15 07:49:18 +00:00
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2022-02-28 07:59:21 +00:00
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Ad esempio,
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2021-06-15 07:49:18 +00:00
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2022-02-28 07:59:21 +00:00
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$$\begin{align} & 9! = 362880 \\; \text{so} \\; f(9) = 36288 \\\\ & 10! = 3628800 \\; \text{so} \\; f(10) = 36288 \\\\ & 20! = 2432902008176640000 \\; \text{so} \\; f(20) = 17664 \end{align}$$
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2021-06-15 07:49:18 +00:00
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2022-02-28 07:59:21 +00:00
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Trova $f(1,000,000,000,000)$
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2021-06-15 07:49:18 +00:00
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# --hints--
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2022-02-28 07:59:21 +00:00
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`factorialTrailingDigits()` dovrebbe restituire `16576`.
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2021-06-15 07:49:18 +00:00
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```js
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assert.strictEqual(factorialTrailingDigits(), 16576);
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2021-06-15 07:49:18 +00:00
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```
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# --seed--
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## --seed-contents--
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```js
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2022-02-28 07:59:21 +00:00
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function factorialTrailingDigits() {
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return true;
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}
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2022-02-28 07:59:21 +00:00
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factorialTrailingDigits();
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2021-06-15 07:49:18 +00:00
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```
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# --solutions--
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```js
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// solution required
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```
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