51 lines
878 B
Markdown
51 lines
878 B
Markdown
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---
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id: 5900f53a1000cf542c51004c
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title: 'Problem 461: Almost Pi'
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challengeType: 5
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forumTopicId: 302136
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dashedName: problem-461-almost-pi
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---
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# --description--
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Let fn(k) = ek/n - 1, for all non-negative integers k.
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Remarkably, f200(6) + f200(75) + f200(89) + f200(226) = 3.141592644529… ≈ π.
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In fact, it is the best approximation of π of the form fn(a) + fn(b) + fn(c) + fn(d) for n = 200.
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Let g(n) = a2 + b2 + c2 + d 2 for a, b, c, d that minimize the error: | fn(a) + fn(b) + fn(c) + fn(d) - π|
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(where |x| denotes the absolute value of x).
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You are given g(200) = 62 + 752 + 892 + 2262 = 64658.
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Find g(10000).
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# --hints--
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`euler461()` should return 159820276.
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```js
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assert.strictEqual(euler461(), 159820276);
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```
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# --seed--
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## --seed-contents--
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```js
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function euler461() {
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return true;
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}
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euler461();
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```
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# --solutions--
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```js
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// solution required
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```
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