diff --git a/guide/english/certifications/coding-interview-prep/project-euler/problem-13-large-sum/index.md b/guide/english/certifications/coding-interview-prep/project-euler/problem-13-large-sum/index.md
index 1dd8d595fa7..0b3444a2d63 100644
--- a/guide/english/certifications/coding-interview-prep/project-euler/problem-13-large-sum/index.md
+++ b/guide/english/certifications/coding-interview-prep/project-euler/problem-13-large-sum/index.md
@@ -1,10 +1,36 @@
---
title: Large sum
---
+
## Problem 13: Large sum
+Challenge: Work out the first ten digits of the sum of one-hundred 50-digit numbers.
-This is a stub. Help our community expand it.
+## Spoiler Alert!
-This quick style guide will help ensure your pull request gets accepted.
+## One Solution:
+```
+function largeSum(arr) {
+ let sum = arr.reduce((acc, item) => acc + Number(item), 0); // 8.348422521139211e+49
+ let str = sum.toString().split('e')[0]; // '8.348422521139211'
+ return 1e+9 * str.slice(0,11); // 8348422521
+}
-
+const testNums = [
+ '37107287533902102798797998220837590246510135740250',
+ '46376937677490009712648124896970078050417018260538'
+];
+
+largeSum(testNums);
+```
+### Code Explanation:
+
+* The function receives an array of strings
+* The first line converts the strings to numbers and adds them
+* The second line converts the large sum to a string with toString, then gets everything to the left of 'e' using String.split().
+* The third line multiplies 1,000,000,000 by the first 11 characters to implicitly coerce the string to a 10 digit number
+* Note: One regular expression could accomplish the same task as the second and third lines together
+
+### Resources
+
+* Array.reduce()
+* String.split()