fix(curriculum): rework Project Euler 52 (#42434)
* fix: rework challenge to use argument in function * fix: update solutionpull/42469/head
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@ -10,20 +10,26 @@ dashedName: problem-52-permuted-multiples
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It can be seen that the number, 125874, and its double, 251748, contain exactly the same digits, but in a different order.
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Find the smallest positive integer, `x`, such that `2x`, `3x`, `4x`, `5x`, and `6x`, contain the same digits.
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Find the smallest positive integer, such that multiplied by integers $\\{2, 3, \ldots, n\\}$, contain the same digits.
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# --hints--
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`permutedMultiples()` should return a number.
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`permutedMultiples(2)` should return a number.
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```js
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assert(typeof permutedMultiples() === 'number');
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assert(typeof permutedMultiples(2) === 'number');
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```
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`permutedMultiples()` should return 142857.
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`permutedMultiples(2)` should return `125874`.
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```js
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assert.strictEqual(permutedMultiples(), 142857);
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assert.strictEqual(permutedMultiples(2), 125874);
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```
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`permutedMultiples(6)` should return `142857`.
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```js
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assert.strictEqual(permutedMultiples(6), 142857);
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```
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# --seed--
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@ -31,18 +37,18 @@ assert.strictEqual(permutedMultiples(), 142857);
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## --seed-contents--
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```js
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function permutedMultiples() {
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function permutedMultiples(n) {
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return true;
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}
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permutedMultiples();
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permutedMultiples(2);
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```
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# --solutions--
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```js
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function permutedMultiples() {
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function permutedMultiples(n) {
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const isPermutation = (a, b) =>
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a.length !== b.length
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? false
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@ -55,9 +61,9 @@ function permutedMultiples() {
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while (!found) {
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start *= 10;
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for (let i = start; i < start * 10 / 6; i++) {
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for (let i = start; i < start * 10 / n; i++) {
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found = true;
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for (let j = 2; j <= 6; j++) {
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for (let j = 2; j <= n; j++) {
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if (!isPermutation(i + '', j * i + '')) {
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found = false;
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break;
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