---
id: 56533eb9ac21ba0edf2244e1
title: Nesting For Loops
challengeType: 1
videoUrl: 'https://scrimba.com/c/cRn6GHM'
forumTopicId: 18248
---

# --description--

If you have a multi-dimensional array, you can use the same logic as the prior waypoint to loop through both the array and any sub-arrays. Here is an example:

```js
var arr = [
  [1,2], [3,4], [5,6]
];
for (var i=0; i < arr.length; i++) {
  for (var j=0; j < arr[i].length; j++) {
    console.log(arr[i][j]);
  }
}
```

This outputs each sub-element in `arr` one at a time. Note that for the inner loop, we are checking the `.length` of `arr[i]`, since `arr[i]` is itself an array.

# --instructions--

Modify function `multiplyAll` so that it returns the product of all the numbers in the sub-arrays of `arr`.

# --hints--

`multiplyAll([[1],[2],[3]])` should return `6`

```js
assert(multiplyAll([[1], [2], [3]]) === 6);
```

`multiplyAll([[1,2],[3,4],[5,6,7]])` should return `5040`

```js
assert(
  multiplyAll([
    [1, 2],
    [3, 4],
    [5, 6, 7]
  ]) === 5040
);
```

`multiplyAll([[5,1],[0.2, 4, 0.5],[3, 9]])` should return `54`

```js
assert(
  multiplyAll([
    [5, 1],
    [0.2, 4, 0.5],
    [3, 9]
  ]) === 54
);
```

# --seed--

## --seed-contents--

```js
function multiplyAll(arr) {
  var product = 1;
  // Only change code below this line

  // Only change code above this line
  return product;
}

multiplyAll([[1,2],[3,4],[5,6,7]]);
```

# --solutions--

```js
function multiplyAll(arr) {
  var product = 1;
  for (var i = 0; i < arr.length; i++) {
    for (var j = 0; j < arr[i].length; j++) {
      product *= arr[i][j];
    }
  }
  return product;
}

multiplyAll([[1,2],[3,4],[5,6,7]]);
```