---
id: 5900f3b31000cf542c50fec6
challengeType: 5
title: 'Problem 71: Ordered fractions'
forumTopicId: 302184
---

## Description
<section id='description'>
Consider the fraction, n/d, where n and d are positive integers. If n<d and HCF(n,d)=1, it is called a reduced proper fraction.
If we list the set of reduced proper fractions for d ≤ 8 in ascending order of size, we get:
1/8, 1/7, 1/6, 1/5, 1/4, 2/7, 1/3, 3/8, 2/5, 3/7, 1/2, 4/7, 3/5, 5/8, 2/3, 5/7, 3/4, 4/5, 5/6, 6/7, 7/8
It can be seen that 2/5 is the fraction immediately to the left of 3/7.
By listing the set of reduced proper fractions for d ≤ 1,000,000 in ascending order of size, find the numerator of the fraction immediately to the left of 3/7.
</section>

## Instructions
<section id='instructions'>

</section>

## Tests
<section id='tests'>

```yml
tests:
  - text: <code>euler71()</code> should return 428570.
    testString: assert.strictEqual(euler71(), 428570);

```

</section>

## Challenge Seed
<section id='challengeSeed'>

<div id='js-seed'>

```js
function euler71() {
  // Good luck!
  return true;
}

euler71();
```

</div>



</section>

## Solution
<section id='solution'>

```js
// solution required
```

</section>