--- id: a3566b1109230028080c9345 title: Sum All Numbers in a Range isRequired: true challengeType: 5 --- ## Description
We'll pass you an array of two numbers. Return the sum of those two numbers plus the sum of all the numbers between them. The lowest number will not always come first. For example, sumAll([4,1]) should return 10 because sum of all the numbers between 1 and 4 (both inclusive) is 10. Remember to use Read-Search-Ask if you get stuck. Try to pair program. Write your own code.
## Instructions
## Tests
```yml tests: - text: sumAll([1, 4]) should return a number. testString: assert(typeof sumAll([1, 4]) === 'number', 'sumAll([1, 4]) should return a number.'); - text: sumAll([1, 4]) should return 10. testString: assert.deepEqual(sumAll([1, 4]), 10, 'sumAll([1, 4]) should return 10.'); - text: sumAll([4, 1]) should return 10. testString: assert.deepEqual(sumAll([4, 1]), 10, 'sumAll([4, 1]) should return 10.'); - text: sumAll([5, 10]) should return 45. testString: assert.deepEqual(sumAll([5, 10]), 45, 'sumAll([5, 10]) should return 45.'); - text: sumAll([10, 5]) should return 45. testString: assert.deepEqual(sumAll([10, 5]), 45, 'sumAll([10, 5]) should return 45.'); ```
## Challenge Seed
```js function sumAll(arr) { return 1; } sumAll([1, 4]); ```
## Solution
```js function sumAll(arr) { var sum = 0; arr.sort(function(a,b) {return a-b;}); for (var i = arr[0]; i <= arr[1]; i++) { sum += i; } return sum; } ```