--- id: 56533eb9ac21ba0edf2244b1 title: Compound Assignment With Augmented Multiplication challengeType: 1 videoUrl: 'https://scrimba.com/c/c83vrfa' forumTopicId: 16662 --- ## Description
The *= operator multiplies a variable by a number. myVar = myVar * 5; will multiply myVar by 5. This can be rewritten as: myVar *= 5;
## Instructions
Convert the assignments for a, b, and c to use the *= operator.
## Tests
```yml tests: - text: a should equal 25. testString: assert(a === 25); - text: b should equal 36. testString: assert(b === 36); - text: c should equal 46. testString: assert(c === 46); - text: You should use the *= operator for each variable. testString: assert(code.match(/\*=/g).length === 3); - text: You should not modify the code above the specified comment. testString: assert(/var a = 5;/.test(code) && /var b = 12;/.test(code) && /var c = 4\.6;/.test(code)); ```
## Challenge Seed
```js var a = 5; var b = 12; var c = 4.6; // Only modify code below this line a = a * 5; b = 3 * b; c = c * 10; ```
### After Test
```js (function(a,b,c){ return "a = " + a + ", b = " + b + ", c = " + c; })(a,b,c); ```
## Solution
```js var a = 5; var b = 12; var c = 4.6; a *= 5; b *= 3; c *= 10; ```