--- id: 5900f5311000cf542c510042 challengeType: 5 title: 'Problem 451: Modular inverses' forumTopicId: 302124 --- ## Description
Consider the number 15. There are eight positive numbers less than 15 which are coprime to 15: 1, 2, 4, 7, 8, 11, 13, 14. The modular inverses of these numbers modulo 15 are: 1, 8, 4, 13, 2, 11, 7, 14 because 1*1 mod 15=1 2*8=16 mod 15=1 4*4=16 mod 15=1 7*13=91 mod 15=1 11*11=121 mod 15=1 14*14=196 mod 15=1 Let I(n) be the largest positive number m smaller than n-1 such that the modular inverse of m modulo n equals m itself. So I(15)=11. Also I(100)=51 and I(7)=1. Find ∑I(n) for 3≤n≤2·107
## Instructions
## Tests
```yml tests: - text: euler451() should return 153651073760956. testString: assert.strictEqual(euler451(), 153651073760956); ```
## Challenge Seed
```js function euler451() { return true; } euler451(); ```
## Solution
```js // solution required ```