--- id: 5900f3b31000cf542c50fec6 challengeType: 5 title: 'Problem 71: Ordered fractions' forumTopicId: 302184 --- ## Description
Consider the fraction, n/d, where n and d are positive integers. If n<d and HCF(n,d)=1, it is called a reduced proper fraction. If we list the set of reduced proper fractions for d ≤ 8 in ascending order of size, we get:
1/8, 1/7, 1/6, 1/5, 1/4, 2/7, 1/3, 3/8, 2/5, 3/7, 1/2, 4/7, 3/5, 5/8, 2/3, 5/7, 3/4, 4/5, 5/6, 6/7, 7/8
It can be seen that 2/5 is the fraction immediately to the left of 3/7. By listing the set of reduced proper fractions for d ≤ 1,000,000 in ascending order of size, find the numerator of the fraction immediately to the left of 3/7.
## Instructions
## Tests
```yml tests: - text: orderedFractions() should return a number. testString: assert(typeof orderedFractions() === 'number'); - text: orderedFractions() should return 428570. testString: assert.strictEqual(orderedFractions(), 428570); ```
## Challenge Seed
```js function orderedFractions() { return true; } orderedFractions(); ```
## Solution
```js // solution required ```