--- id: 5a23c84252665b21eecc801c title: Spiral matrix challengeType: 5 forumTopicId: 302321 --- ## Description
Produce a spiral array. A spiral array is a square arrangement of the first N2 natural numbers, where the numbers increase sequentially as you go around the edges of the array spiraling inwards. For example, given 5, produce this array:
0  1  2  3  4
15 16 17 18 5
14 23 24 19 6
13 22 21 20 7
12 11 10  9 8
## Instructions
## Tests
```yml tests: - text: spiralArray should be a function. testString: assert(typeof spiralArray=='function'); - text: spiralArray(3) should return an array. testString: assert(Array.isArray(spiralArray(3))); - text: spiralArray(3) should return [[0, 1, 2],[7, 8, 3],[6, 5, 4]]. testString: assert.deepEqual(spiralArray(3), [[0, 1, 2], [7, 8, 3], [6, 5, 4]]); - text: spiralArray(4) should return [[0, 1, 2, 3],[11, 12, 13, 4],[10, 15, 14, 5],[9, 8, 7, 6]]. testString: assert.deepEqual(spiralArray(4), [[0, 1, 2, 3], [11, 12, 13, 4], [10, 15, 14, 5], [9, 8, 7, 6]]); - text: spiralArray(5) should return [[0, 1, 2, 3, 4],[15, 16, 17, 18, 5],[14, 23, 24, 19, 6],[13, 22, 21, 20, 7],[12, 11, 10, 9, 8]]. testString: assert.deepEqual(spiralArray(5), [[0, 1, 2, 3, 4], [15, 16, 17, 18, 5], [14, 23, 24, 19, 6], [13, 22, 21, 20, 7], [12, 11, 10, 9, 8]]); ```
## Challenge Seed
```js function spiralArray(n) { } ```
## Solution
```js function spiralArray(n) { var arr = Array(n), x = 0, y = n, total = n * n--, dx = 1, dy = 0, i = 0, j = 0; while (y) arr[--y] = []; while (i < total) { arr[y][x] = i++; x += dx; y += dy; if (++j == n) { if (dy < 0) { x++; y++; n -= 2; } j = dx; dx = -dy; dy = j; j = 0; } } return arr; } ```