--- id: 587d8254367417b2b2512c6f title: 对两组数据执行子集检查 challengeType: 1 videoUrl: '' dashedName: perform-a-subset-check-on-two-sets-of-data --- # --description-- 在本练习中,我们将对2组数据执行子集测试。我们将在我们的`Set`数据结构上创建一个名为`subset` 。这将比较第一组与第二组,如果第一组完全包含在第二组中,则它将返回true。例如,如果`setA = ['a','b']`和`setB = ['a','b','c','d']` ,则setA和setB的子集为: `setA.subset(setB)`应该是`true` 。 # --hints-- 你的`Set`类应该有一个`union`方法。 ```js assert( (function () { var test = new Set(); return typeof test.subset === 'function'; })() ); ``` 第一个Set()包含在第二个Set中 ```js assert( (function () { var setA = new Set(); var setB = new Set(); setA.add('a'); setB.add('b'); setB.add('c'); setB.add('a'); setB.add('d'); var subsetSetAB = setA.subset(setB); return subsetSetAB === true; })() ); ``` `["a", "b"].subset(["a", "b", "c", "d"])`应该返回`true` “) ```js assert( (function () { var setA = new Set(); var setB = new Set(); setA.add('a'); setA.add('b'); setB.add('a'); setB.add('b'); setB.add('c'); setB.add('d'); var subsetSetAB = setA.subset(setB); return subsetSetAB === true; })() ); ``` `["a", "b", "c"].subset(["a", "b"])`应返回`false` “) ```js assert( (function () { var setA = new Set(); var setB = new Set(); setA.add('a'); setA.add('b'); setA.add('c'); setB.add('a'); setB.add('b'); var subsetSetAB = setA.subset(setB); return subsetSetAB === false; })() ); ``` `[].subset([])`应该返回`true` ```js assert( (function () { var setA = new Set(); var setB = new Set(); var subsetSetAB = setA.subset(setB); return subsetSetAB === true; })() ); ``` `["a", "b"].subset(["c", "d"])`应返回`false` “) ```js assert( (function () { var setA = new Set(); var setB = new Set(); setA.add('a'); setA.add('b'); setB.add('c'); setB.add('d'); var subsetSetAB = setA.subset(setB); return subsetSetAB === false; })() ); ``` # --seed-- ## --seed-contents-- ```js class Set { constructor() { // This will hold the set this.dictionary = {}; this.length = 0; } // This method will check for the presence of an element and return true or false has(element) { return this.dictionary[element] !== undefined; } // This method will return all the values in the set values() { return Object.keys(this.dictionary); } // This method will add an element to the set add(element) { if (!this.has(element)) { this.dictionary[element] = true; this.length++; return true; } return false; } // This method will remove an element from a set remove(element) { if (this.has(element)) { delete this.dictionary[element]; this.length--; return true; } return false; } // This method will return the size of the set size() { return this.length; } // This is our union method union(set) { const newSet = new Set(); this.values().forEach(value => { newSet.add(value); }) set.values().forEach(value => { newSet.add(value); }) return newSet; } // This is our intersection method intersection(set) { const newSet = new Set(); let largeSet; let smallSet; if (this.dictionary.length > set.length) { largeSet = this; smallSet = set; } else { largeSet = set; smallSet = this; } smallSet.values().forEach(value => { if (largeSet.dictionary[value]) { newSet.add(value); } }) return newSet; } difference(set) { const newSet = new Set(); this.values().forEach(value => { if (!set.dictionary[value]) { newSet.add(value); } }) return newSet; } // Only change code below this line // Only change code above this line } ``` # --solutions-- ```js class Set { constructor() { this.dictionary = {}; this.length = 0; } has(element) { return this.dictionary[element] !== undefined; } values() { return Object.keys(this.dictionary); } add(element) { if (!this.has(element)) { this.dictionary[element] = true; this.length++; return true; } return false; } remove(element) { if (this.has(element)) { delete this.dictionary[element]; this.length--; return true; } return false; } size() { return this.length; } union(set) { const newSet = new Set(); this.values().forEach(value => { newSet.add(value); }) set.values().forEach(value => { newSet.add(value); }) return newSet; } intersection(set) { const newSet = new Set(); let largeSet; let smallSet; if (this.dictionary.length > set.length) { largeSet = this; smallSet = set; } else { largeSet = set; smallSet = this; } smallSet.values().forEach(value => { if (largeSet.dictionary[value]) { newSet.add(value); } }) return newSet; } difference(set) { const newSet = new Set(); this.values().forEach(value => { if (!set.dictionary[value]) { newSet.add(value); } }) return newSet; } isSubsetOf(set) { for(const value of this.values()){ if(!set.dictionary[value]) return false; } return true } } ```