--- id: 5900f3e71000cf542c50fefa challengeType: 5 title: 'Problem 123: Prime square remainders' --- ## Description
Let pn be the nth prime: 2, 3, 5, 7, 11, ..., and let r be the remainder when (pn−1)n + (pn+1)n is divided by pn2. For example, when n = 3, p3 = 5, and 43 + 63 = 280 ≡ 5 mod 25. The least value of n for which the remainder first exceeds 109 is 7037. Find the least value of n for which the remainder first exceeds 1010.
## Instructions
## Tests
```yml tests: - text: euler123() should return 21035. testString: assert.strictEqual(euler123(), 21035); ```
## Challenge Seed
```js function euler123() { // Good luck! return true; } euler123(); ```
## Solution
```js // solution required ```