--- id: 5900f3c61000cf542c50fed9 challengeType: 5 title: 'Problem 90: Cube digit pairs' --- ## Description
Each of the six faces on a cube has a different digit (0 to 9) written on it; the same is done to a second cube. By placing the two cubes side-by-side in different positions we can form a variety of 2-digit numbers. For example, the square number 64 could be formed: In fact, by carefully choosing the digits on both cubes it is possible to display all of the square numbers below one-hundred: 01, 04, 09, 16, 25, 36, 49, 64, and 81. For example, one way this can be achieved is by placing {0, 5, 6, 7, 8, 9} on one cube and {1, 2, 3, 4, 8, 9} on the other cube. However, for this problem we shall allow the 6 or 9 to be turned upside-down so that an arrangement like {0, 5, 6, 7, 8, 9} and {1, 2, 3, 4, 6, 7} allows for all nine square numbers to be displayed; otherwise it would be impossible to obtain 09. In determining a distinct arrangement we are interested in the digits on each cube, not the order. {1, 2, 3, 4, 5, 6} is equivalent to {3, 6, 4, 1, 2, 5} {1, 2, 3, 4, 5, 6} is distinct from {1, 2, 3, 4, 5, 9} But because we are allowing 6 and 9 to be reversed, the two distinct sets in the last example both represent the extended set {1, 2, 3, 4, 5, 6, 9} for the purpose of forming 2-digit numbers. How many distinct arrangements of the two cubes allow for all of the square numbers to be displayed?
## Instructions
## Tests
```yml tests: - text: euler90() should return 1217. testString: assert.strictEqual(euler90(), 1217); ```
## Challenge Seed
```js function euler90() { // Good luck! return true; } euler90(); ```
## Solution
```js // solution required ```