--- id: 5a23c84252665b21eecc8041 title: Sum of a series challengeType: 5 forumTopicId: 302333 dashedName: sum-of-a-series --- # --description-- Compute the **n**th term of a [series](), i.e. the sum of the **n** first terms of the corresponding [sequence](https://en.wikipedia.org/wiki/sequence). Informally this value, or its limit when **n** tends to infinity, is also called the *sum of the series*, thus the title of this task. For this task, use: $S_n = \displaystyle\sum_{k=1}^n \frac{1}{k^2}$. # --instructions-- Write a function that take $a$ and $b$ as parameters and returns the sum of $a^{th}$ to $b^{th}$ members of the sequence. # --hints-- `sum` should be a function. ```js assert(typeof sum == 'function'); ``` `sum(1, 100)` should return a number. ```js assert(typeof sum(1, 100) == 'number'); ``` `sum(1, 100)` should return `1.6349839001848923`. ```js assert.equal(sum(1, 100), 1.6349839001848923); ``` `sum(33, 46)` should return `0.009262256361481223`. ```js assert.equal(sum(33, 46), 0.009262256361481223); ``` `sum(21, 213)` should return `0.044086990748706555`. ```js assert.equal(sum(21, 213), 0.044086990748706555); ``` `sum(11, 111)` should return `0.08619778593108679`. ```js assert.equal(sum(11, 111), 0.08619778593108679); ``` `sum(1, 10)` should return `1.5497677311665408`. ```js assert.equal(sum(1, 10), 1.5497677311665408); ``` # --seed-- ## --seed-contents-- ```js function sum(a, b) { } ``` # --solutions-- ```js function sum(a, b) { function fn(x) { return 1 / (x * x); } var s = 0; for (; a <= b; a++) s += fn(a); return s; } ```