--- id: 5900f4fd1000cf542c51000f challengeType: 5 title: 'Problem 401: Sum of squares of divisors' --- ## Description
The divisors of 6 are 1,2,3 and 6. The sum of the squares of these numbers is 1+4+9+36=50. Let sigma2(n) represent the sum of the squares of the divisors of n. Thus sigma2(6)=50. Let SIGMA2 represent the summatory function of sigma2, that is SIGMA2(n)=∑sigma2(i) for i=1 to n. The first 6 values of SIGMA2 are: 1,6,16,37,63 and 113. Find SIGMA2(1015) modulo 109.
## Instructions
## Tests
```yml tests: - text: euler401() should return 281632621. testString: assert.strictEqual(euler401(), 281632621, 'euler401() should return 281632621.'); ```
## Challenge Seed
```js function euler401() { // Good luck! return true; } euler401(); ```
## Solution
```js // solution required ```