--- id: 5900f53a1000cf542c51004c challengeType: 5 title: 'Problem 461: Almost Pi' --- ## Description
Let fn(k) = ek/n - 1, for all non-negative integers k. Remarkably, f200(6) + f200(75) + f200(89) + f200(226) = 3.141592644529… ≈ π. In fact, it is the best approximation of π of the form fn(a) + fn(b) + fn(c) + fn(d) for n = 200. Let g(n) = a2 + b2 + c2 + d 2 for a, b, c, d that minimize the error: | fn(a) + fn(b) + fn(c) + fn(d) - π| (where |x| denotes the absolute value of x). You are given g(200) = 62 + 752 + 892 + 2262 = 64658. Find g(10000).
## Instructions
## Tests
```yml tests: - text: euler461() should return 159820276. testString: assert.strictEqual(euler461(), 159820276, 'euler461() should return 159820276.'); ```
## Challenge Seed
```js function euler461() { // Good luck! return true; } euler461(); ```
## Solution
```js // solution required ```