--- title: Day of the week id: 5966f99c45e8976909a85575 challengeType: 5 videoUrl: '' localeTitle: 一周中的天 --- ## Description

一家公司决定,每当圣诞节落在星期天,他们将给予他们的工人所有额外带薪假期,这样,在任何公共假期,工人将不必在下一周(12月25日到1月1日之间)工作。

任务:

编写一个开始年份和结束年份的函数,并返回12月25日为星期日的所有年份的数组。

## Instructions
## Tests
```yml tests: - text: findXmasSunday是一个函数。 testString: 'assert(typeof findXmasSunday === "function", "findXmasSunday is a function.");' - text: 'findChristmasSunday(2000, 2100)应该返回一个数组。' testString: 'assert(typeof findXmasSunday(2000, 2100) === "object", "findChristmasSunday(2000, 2100) should return an array.");' - text: 'findChristmasSunday(2008, 2121应该回归[1977,1983,1988,1994,2005,2011,2016]' testString: 'assert.deepEqual(findXmasSunday(1970, 2017), firstSolution, "findChristmasSunday(2008, 2121 should return [1977, 1983, 1988, 1994, 2005, 2011, 2016]");' - text: 'findChristmasSunday(2008, 2121应该返回[2011,2016,2022,2033,2039,2044,2050,2061,2067,2072,2078,2089,2095,2101,2107,2112,2118]' testString: 'assert.deepEqual(findXmasSunday(2008, 2121), secondSolution, "findChristmasSunday(2008, 2121 should return [2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118]");' ```
## Challenge Seed
```js function findXmasSunday (start, end) { // Good luck! return true; } ```
### After Test
```js console.info('after the test'); ```
## Solution
```js // solution required ```