--- title: Day of the week id: 5966f99c45e8976909a85575 challengeType: 5 --- ## Description

A company decides that whenever Xmas falls on a Sunday they will give their workers all extra paid holidays so that, together with any public holidays, workers will not have to work the following week (between the 25th of December and the first of January).

Task:

Write a function that takes a start year and an end year and return an array of all the years where the 25th of December will be a Sunday.

## Instructions
## Tests
```yml tests: - text: findXmasSunday is a function. testString: 'assert(typeof findXmasSunday === ''function'', ''findXmasSunday is a function.'');' - text: 'findChristmasSunday(2000, 2100) should return an array.' testString: 'assert(typeof findXmasSunday(2000, 2100) === ''object'', ''findChristmasSunday(2000, 2100) should return an array.'');' - text: 'findChristmasSunday(2008, 2121 should return [1977, 1983, 1988, 1994, 2005, 2011, 2016]' testString: 'assert.deepEqual(findXmasSunday(1970, 2017), firstSolution, ''findChristmasSunday(2008, 2121 should return [1977, 1983, 1988, 1994, 2005, 2011, 2016]'');' - text: 'findChristmasSunday(2008, 2121 should return [2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118]' testString: 'assert.deepEqual(findXmasSunday(2008, 2121), secondSolution, ''findChristmasSunday(2008, 2121 should return [2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118]'');' ```
## Challenge Seed
```js function findXmasSunday (start, end) { // Good luck! return true; } ```
### After Test
```js console.info('after the test'); ```
## Solution
```js function findXmasSunday (start, end) { const xmasSunday = []; for (let year = start; year <= end; year++) { const xmas = new Date(year, 11, 25); if (xmas.getDay() === 0) { xmasSunday.push(year); } } return xmasSunday; } ```