--- title: Averages-Pythagorean means id: 594d966a1467eb84194f0086 challengeType: 5 --- ## Description

Compute all three of the Pythagorean means of the set of integers 1 through 10 (inclusive).

Show that $A(x_1,\ldots,x_n) \geq G(x_1,\ldots,x_n) \geq H(x_1,\ldots,x_n)$ for this set of positive integers.

The most common of the three means, the arithmetic mean, is the sum of the list divided by its length: $ A(x_1, \ldots, x_n) = \frac{x_1 + \cdots + x_n}{n}$The geometric mean is the $n$th root of the product of the list: $ G(x_1, \ldots, x_n) = \sqrt[n]{x_1 \cdots x_n} $The harmonic mean is $n$ divided by the sum of the reciprocal of each item in the list: $ H(x_1, \ldots, x_n) = \frac{n}{\frac{1}{x_1} + \cdots + \frac{1}{x_n}} $

Assume the input is an ordered array of all inclusive numbers.

For the answer, please output an object in the following format:

{
  values: {
    Arithmetic: 5.5,
    Geometric: 4.528728688116765,
    Harmonic: 3.414171521474055
  },
  test: 'is A >= G >= H ? yes'
}
## Instructions
## Tests
```yml tests: - text: pythagoreanMeans is a function. testString: 'assert(typeof pythagoreanMeans === "function", "pythagoreanMeans is a function.");' - text: 'pythagoreanMeans([1, 2, ..., 10]) should equal the same output above.' testString: 'assert.deepEqual(pythagoreanMeans(range1), answer1, "pythagoreanMeans([1, 2, ..., 10]) should equal the same output above.");' ```
## Challenge Seed
```js function pythagoreanMeans (rangeArr) { // Good luck! } ```
### After Test
```js console.info('after the test'); ```
## Solution
```js function pythagoreanMeans (rangeArr) { // arithmeticMean :: [Number] -> Number const arithmeticMean = xs => foldl((sum, n) => sum + n, 0, xs) / length(xs); // geometricMean :: [Number] -> Number const geometricMean = xs => raise(foldl((product, x) => product * x, 1, xs), 1 / length(xs)); // harmonicMean :: [Number] -> Number const harmonicMean = xs => length(xs) / foldl((invSum, n) => invSum + (1 / n), 0, xs); // GENERIC FUNCTIONS ------------------------------------------------------ // A list of functions applied to a list of arguments // <*> :: [(a -> b)] -> [a] -> [b] const ap = (fs, xs) => // Array.prototype.concat(...fs.map(f => // Array.prototype.concat(...xs.map(x => [f(x)])))); // foldl :: (b -> a -> b) -> b -> [a] -> b const foldl = (f, a, xs) => xs.reduce(f, a); // length :: [a] -> Int const length = xs => xs.length; // mapFromList :: [(k, v)] -> Dictionary const mapFromList = kvs => foldl((a, [k, v]) => (a[(typeof k === 'string' && k)] = v, a), {}, kvs); // raise :: Num -> Int -> Num const raise = (n, e) => Math.pow(n, e); /* // show :: a -> String // show :: a -> Int -> String const show = (...x) => JSON.stringify.apply( null, x.length > 1 ? [x[0], null, x[1]] : x ); */ // zip :: [a] -> [b] -> [(a,b)] const zip = (xs, ys) => xs.slice(0, Math.min(xs.length, ys.length)) .map((x, i) => [x, ys[i]]); // TEST ------------------------------------------------------------------- // mean :: Dictionary const mean = mapFromList(zip( ['Arithmetic', 'Geometric', 'Harmonic'], ap([arithmeticMean, geometricMean, harmonicMean], [ rangeArr ]) )); return { values: mean, test: `is A >= G >= H ? ${mean.Arithmetic >= mean.Geometric && mean.Geometric >= mean.Harmonic ? 'yes' : 'no'}` }; } ```