--- title: Vector dot product id: 594810f028c0303b75339ad3 challengeType: 5 --- ## Description

A vector is defined as having three dimensions as being represented by an ordered collection of three numbers:   (X, Y, Z).

Task: Write a function that takes any numbers of vectors (arrays) as input and computes their dot product. Your function should return null on invalid inputs (ie vectors of different lengths).

## Instructions
## Tests
```yml tests: - text: dotProduct must be a function testString: 'assert.equal(typeof dotProduct, "function", "dotProduct must be a function");' - text: dotProduct() must return null testString: 'assert.equal(dotProduct(), null, "dotProduct() must return null");' - text: 'dotProduct([[1], [1]]) must return 1.' testString: 'assert.equal(dotProduct([1], [1]), 1, "dotProduct([[1], [1]]) must return 1.");' - text: 'dotProduct([[1], [1, 2]]) must return null.' testString: 'assert.equal(dotProduct([1], [1, 2]), null, "dotProduct([[1], [1, 2]]) must return null.");' - text: 'dotProduct([1, 3, -5], [4, -2, -1]) must return 3.' testString: 'assert.equal(dotProduct([1, 3, -5], [4, -2, -1]), 3, "dotProduct([1, 3, -5], [4, -2, -1]) must return 3.");' - text: dotProduct(...nVectors) should return 156000 testString: 'assert.equal(dotProduct([ 0, 1, 2, 3, 4 ], [ 0, 2, 4, 6, 8 ], [ 0, 3, 6, 9, 12 ], [ 0, 4, 8, 12, 16 ], [ 0, 5, 10, 15, 20 ]), 156000, "dotProduct(...nVectors) should return 156000");' ```
## Challenge Seed
```js function dotProduct() { // Good luck! } ```
## Solution
```js function dotProduct(...vectors) { if (!vectors || !vectors.length) { return null; } if (!vectors[0] || !vectors[0].length) { return null; } const vectorLen = vectors[0].length; const numVectors = vectors.length; // If all vectors not same length, return null for (let i = 0; i < numVectors; i++) { if (vectors[i].length !== vectorLen) { return null; // return undefined } } let prod = 0; let sum = 0; let j = vectorLen; let i = numVectors; // Sum terms while (j--) { i = numVectors; prod = 1; while (i--) { prod *= vectors[i][j]; } sum += prod; } return sum; } ```