--- id: 5900f3711000cf542c50fe84 challengeType: 5 title: 'Problem 5: Smallest multiple' --- ## Description
2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder. What is the smallest positive number that is evenly divisible by all of the numbers from 1 to n?
## Instructions
## Tests
```yml tests: - text: smallestMult(5) should return 60. testString: assert.strictEqual(smallestMult(5), 60, 'smallestMult(5) should return 60.'); - text: smallestMult(7) should return 420. testString: assert.strictEqual(smallestMult(7), 420, 'smallestMult(7) should return 420.'); - text: smallestMult(10) should return 2520. testString: assert.strictEqual(smallestMult(10), 2520, 'smallestMult(10) should return 2520.'); - text: smallestMult(13) should return 360360. testString: assert.strictEqual(smallestMult(13), 360360, 'smallestMult(13) should return 360360.'); - text: smallestMult(20) should return 232792560. testString: assert.strictEqual(smallestMult(20), 232792560, 'smallestMult(20) should return 232792560.'); ```
## Challenge Seed
```js function smallestMult(n) { // Good luck! return true; } smallestMult(20); ```
## Solution
```js function smallestMult(n){ function gcd(a, b) { return b === 0 ? a : gcd(b, a%b); // Euclidean algorithm } function lcm(a, b) { return a * b / gcd(a, b); } var result = 1; for(var i = 2; i <= n; i++) { result = lcm(result, i); } return result; } ```