--- id: 5900f3761000cf542c50fe88 challengeType: 5 videoUrl: '' localeTitle: 问题9:特殊的毕达哥拉斯三重奏 --- ## Description
毕达哥拉斯三元组是一组三个自然数, a < b < c ,其中,
a 2 + b 2 = c 2
例如,3 2 + 4 2 = 9 + 16 = 25 = 5 2 。恰好存在一个毕达哥拉斯三元组,其中a + b + c = 1000.求产品abc使得a + b + c = n
## Instructions
## Tests
```yml tests: - text: specialPythagoreanTriplet(1000)应返回31875000。 testString: assert.strictEqual(specialPythagoreanTriplet(1000), 31875000); - text: specialPythagoreanTriplet(24)应该返回480。 testString: assert.strictEqual(specialPythagoreanTriplet(24), 480); - text: specialPythagoreanTriplet(120)应该返回49920。 testString: assert([49920, 55080, 60000].includes(specialPythagoreanTriplet(120))); ```
## Challenge Seed
```js function specialPythagoreanTriplet(n) { let sumOfabc = n; // Good luck! return true; } specialPythagoreanTriplet(1000); ```
## Solution
```js // solution required ``` /section>