--- id: 587d8254367417b2b2512c6e title: Perform a Difference on Two Sets of Data challengeType: 1 videoUrl: '' localeTitle: 对两组数据执行差异 --- ## Description
在本练习中,我们将对两组数据进行区分。我们将在我们的Set数据结构上创建一个名为difference 。集合的差异应比较两组并返回第一组中不存在的项目。此方法应将另一个Set作为参数,并返回两个集的difference 。例如,如果setA = ['a','b','c']setB = ['a','b','d','e'] ,则setA和setB的差异为: setA.difference(setB) = ['c']
## Instructions
## Tests
```yml tests: - text: 你的Set类应该有一个difference方法。 testString: 'assert(function(){var test = new Set(); return (typeof test.difference === "function")}, "Your Set class should have a difference method.");' - text: 收回了适当的收藏 testString: 'assert(function(){var setA = new Set(); var setB = new Set(); setA.add("a"); setA.add("b"); setA.add("c"); setB.add("c"); setB.add("d"); var differenceSetAB = setA.difference(setB); return (differenceSetAB.size() === 2) && (differenceSetAB.values() === [ "a", "b" ])}, "The proper collection was returned");' ```
## Challenge Seed
```js function Set() { // the var collection will hold the set var collection = []; // this method will check for the presence of an element and return true or false this.has = function(element) { return (collection.indexOf(element) !== -1); }; // this method will return all the values in the set this.values = function() { return collection; }; // this method will add an element to the set this.add = function(element) { if(!this.has(element)){ collection.push(element); return true; } return false; }; // this method will remove an element from a set this.remove = function(element) { if(this.has(element)){ var index = collection.indexOf(element); collection.splice(index,1); return true; } return false; }; // this method will return the size of the collection this.size = function() { return collection.length; }; // this method will return the union of two sets this.union = function(otherSet) { var unionSet = new Set(); var firstSet = this.values(); var secondSet = otherSet.values(); firstSet.forEach(function(e){ unionSet.add(e); }); secondSet.forEach(function(e){ unionSet.add(e); }); return unionSet; }; // this method will return the intersection of two sets as a new set this.intersection = function(otherSet) { var intersectionSet = new Set(); var firstSet = this.values(); firstSet.forEach(function(e){ if(otherSet.has(e)){ intersectionSet.add(e); } }); return intersectionSet; }; // change code below this line // change code above this line } ```
## Solution
```js // solution required ```