---
title: Count occurrences of a substring
id: 596fda99c69f779975a1b67d
challengeType: 5
videoUrl: ''
localeTitle: 计算子字符串的出现次数
---

## Description
<section id="description">任务： <p>创建函数或显示内置函数，以计算字符串中子字符串的非重叠出现次数。 </p><p>该函数应该有两个参数： </p>第一个参数是要搜索的字符串，第二个参数是要搜索的子字符串。 <p>它应该返回一个整数计数。 </p><p>匹配应产生最多数量的非重叠匹配。 </p><p>通常，这实质上意味着从左到右或从右到左匹配。 </p></section>

## Instructions
<section id="instructions">
</section>

## Tests
<section id='tests'>

```yml
tests:
  - text: <code>countSubstring</code>是一个函数。
    testString: 'assert(typeof countSubstring === "function", "<code>countSubstring</code> is a function.");'
  - text: '<code>countSubstring(&quot;the three truths&quot;, &quot;th&quot;)</code>应该返回<code>3</code> 。'
    testString: 'assert.equal(countSubstring(testCases[0], searchString[0]), results[0], "<code>countSubstring("the three truths", "th")</code> should return <code>3</code>.");'
  - text: '<code>countSubstring(&quot;ababababab&quot;, &quot;abab&quot;)</code>应返回<code>2</code> 。'
    testString: 'assert.equal(countSubstring(testCases[1], searchString[1]), results[1], "<code>countSubstring("ababababab", "abab")</code> should return <code>2</code>.");'
  - text: '<code>countSubstring(&quot;abaabba*bbaba*bbab&quot;, &quot;a*b&quot;)</code>应返回<code>2</code> 。'
    testString: 'assert.equal(countSubstring(testCases[2], searchString[2]), results[2], "<code>countSubstring("abaabba*bbaba*bbab", "a*b")</code> should return <code>2</code>.");'

```

</section>

## Challenge Seed
<section id='challengeSeed'>

<div id='js-seed'>

```js
function countSubstring (str, subStr) {
  // Good luck!
  return true;
}

```

</div>


### After Test
<div id='js-teardown'>

```js
console.info('after the test');
```

</div>

</section>

## Solution
<section id='solution'>

```js
// solution required
```
</section>