--- id: 5e6dd1278e6ca105cde40ea9 title: Longest common subsequence challengeType: 5 forumTopicId: 385271 --- # --description-- The **longest common subsequence** (or [**LCS**](http://en.wikipedia.org/wiki/Longest_common_subsequence_problem)) of groups A and B is the longest group of elements from A and B that are common between the two groups and in the same order in each group. For example, the sequences "1234" and "1224533324" have an LCS of "1234": ***1234*** ***12***245***3***332***4*** For a string example, consider the sequences "thisisatest" and "testing123testing". An LCS would be "tsitest": ***t***hi***si***sa***test*** ***t***e***s***t***i***ng123***test***ing. Your code only needs to deal with strings. For more information on this problem please see [Wikipedia](https://en.wikipedia.org/wiki/Longest_common_subsequence_problem). # --instructions-- Write a case-sensitive function that returns the LCS of two strings. You don't need to show multiple LCS's. # --hints-- `lcs` should be a function. ```js assert(typeof lcs == 'function'); ``` `lcs("thisisatest", "testing123testing")` should return a string. ```js assert(typeof lcs('thisisatest', 'testing123testing') == 'string'); ``` `lcs("thisisatest", "testing123testing")` should return `"tsitest"`. ```js assert.equal(lcs('thisisatest', 'testing123testing'), 'tsitest'); ``` `lcs("ABCDGH", "AEDFHR")` should return `"ADH"`. ```js assert.equal(lcs('ABCDGH', 'AEDFHR'), 'ADH'); ``` `lcs("AGGTAB", "GXTXAYB")` should return `"GTAB"`. ```js assert.equal(lcs('AGGTAB', 'GXTXAYB'), 'GTAB'); ``` `lcs("BDACDB", "BDCB")` should return `"BDCB"`. ```js assert.equal(lcs('BDACDB', 'BDCB'), 'BDCB'); ``` `lcs("ABAZDC", "BACBAD")` should return `"ABAD"`. ```js assert.equal(lcs('ABAZDC', 'BACBAD'), 'ABAD'); ``` # --seed-- ## --seed-contents-- ```js function lcs(a, b) { } ``` # --solutions-- ```js function lcs(a, b) { var aSub = a.substr(0, a.length - 1); var bSub = b.substr(0, b.length - 1); if (a.length === 0 || b.length === 0) { return ''; } else if (a.charAt(a.length - 1) === b.charAt(b.length - 1)) { return lcs(aSub, bSub) + a.charAt(a.length - 1); } else { var x = lcs(a, bSub); var y = lcs(aSub, b); return (x.length > y.length) ? x : y; } } ```