--- title: Binary Agents --- ![](//discourse-user-assets.s3.amazonaws.com/original/2X/7/70cf3cc5462f69c2f770ad42d0f24f240a8d8f13.jpg) ![:triangular_flag_on_post:](https://forum.freecodecamp.com/images/emoji/emoji_one/triangular_flag_on_post.png?v=3 ":triangular_flag_on_post:") Remember to use **`Read-Search-Ask`** if you get stuck. Try to pair program ![:busts_in_silhouette:](https://forum.freecodecamp.com/images/emoji/emoji_one/busts_in_silhouette.png?v=3 ":busts_in_silhouette:") and write your own code ![:pencil:](https://forum.freecodecamp.com/images/emoji/emoji_one/pencil.png?v=3 ":pencil:") ## Problem Explanation: This problem is very straight forward - you start with a string that represents a sentence in binary code, and you need to translate that into words. There is not a direct way to do this so you will have to translate twice. ### Relevant Links * String.prototype.charCodeAt * String.fromCharCode ## ![:speech_balloon:](https://forum.freecodecamp.com/images/emoji/emoji_one/speech_balloon.png?v=3 ":speech_balloon:") Hint: 1 You should first convert from **binary** to **decimal** before translating those values into characters. > _try to solve the problem now_ ## ![:speech_balloon:](https://forum.freecodecamp.com/images/emoji/emoji_one/speech_balloon.png?v=3 ":speech_balloon:") Hint: 2 Things are easier when focusing on smaller parts, divide the input to focus on one letter at a time. > _try to solve the problem now_ ## ![:speech_balloon:](https://forum.freecodecamp.com/images/emoji/emoji_one/speech_balloon.png?v=3 ":speech_balloon:") Hint: 3 Make sure that each time you transcode a character from binary to decimal, you reset whatever variable you used to keep track of the ones. Also do not forget to turn everything back into one string. > _try to solve the problem now_ ## Spoiler Alert! ![warning sign](//discourse-user-assets.s3.amazonaws.com/original/2X/2/2d6c412a50797771301e7ceabd554cef4edcd74d.gif) **Solution ahead!** ## ![:beginner:](https://forum.freecodecamp.com/images/emoji/emoji_one/beginner.png?v=3 ":beginner:") Basic Code Solution: ```javascript function binaryAgent(str) { biString = str.split(' '); uniString = []; /*using the radix (or base) parameter in parseInt, we can convert the binary number to a decimal number while simultaneously converting to a char*/ for(i=0;i < biString.length;i++){ uniString.push(String.fromCharCode(parseInt(biString[i], 2))); } // we then simply join the string return uniString.join(''); } // test here binaryAgent("01000001 01110010 01100101 01101110 00100111 01110100 00100000 01100010 01101111 01101110 01100110 01101001 01110010 01100101 01110011 00100000 01100110 01110101 01101110 00100001 00111111"); ``` ![:rocket:](https://forum.freecodecamp.com/images/emoji/emoji_one/rocket.png?v=3 ":rocket:") Run Code # Code Explanation: * Separate the string into an array of strings separated by whitespace. * Create some variables that you will use along the way - the names are self explanatory for the most part. * Iterate through each binary string in the new array. * Convert to decimal by using `parseInt(_binary_, 2)`. Use the second parameter to specify the base of the input numbers. * At the end, return the converted message. ## Relevant Links * String.prototype.split * parseInt ## ![:sunflower:](https://forum.freecodecamp.com/images/emoji/emoji_one/sunflower.png?v=3 ":sunflower:") Intermediate Code Solution: ```javascript function binaryAgent(str) { // Separate the binary code by space. str = str.split(' '); var power; var decValue = 0; var sentence = ''; // Check each binary number from the array. for (var s = 0; s < str.length; s++) { // Check each bit from binary number for (var t = 0; t < str[s].length; t++) { // This only takes into consideration the active ones. if (str[s][t] == 1) { // This is quivalent to 2 ** position power = Math.pow(2, +str[s].length - t - 1); decValue += power; // Record the decimal value by adding the number to the previous one. } } // After the binary number is converted to decimal, convert it to string and store sentence += (String.fromCharCode(decValue)); // Reset decimal value for next binary number. decValue = 0; } return sentence; } // test here binaryAgent("01000001 01110010 01100101 01101110 00100111 01110100 00100000 01100010 01101111 01101110 01100110 01101001 01110010 01100101 01110011 00100000 01100110 01110101 01101110 00100001 00111111"); ``` ![:rocket:](https://forum.freecodecamp.com/images/emoji/emoji_one/rocket.png?v=3 ":rocket:") Run Code # Code Explanation * For each of these binary strings, check for the ones and ignore the zeroes. * For those that are one or active then convert them to decimal, this takes into account the position and the right power it needs to be raised to. * Store the power into the **power** variable by adding it to any previous ones on the variable **decValue**. This variable will add and add the powers of the active ones until the end of the loop and then return the decimal number. * Convert the final decimal outside of the inner loop and then convert it to ASCII and saving it to **sentence** along with any other text string already converted and stored. * Reset the variable **decValue** to avoid getting wrong decimals before continuing to the outer loop. ## Relevant Links * Math.pow * String.length * Link Title 3 ## ![:rotating_light:](https://forum.freecodecamp.com/images/emoji/emoji_one/rotating_light.png?v=3 ":rotating_light:") Advanced Code Solution: ```javascript function binaryAgent(str) { return String.fromCharCode(...str.split(" ").map(function(char){ return parseInt(char, 2); })); } // test here binaryAgent("01000001 01110010 01100101 01101110 00100111 01110100 00100000 01100010 01101111 01101110 01100110 01101001 01110010 01100101 01110011 00100000 01100110 01110101 01101110 00100001 00111111"); ``` ![:rocket:](https://forum.freecodecamp.com/images/emoji/emoji_one/rocket.png?v=3 ":rocket:") Run Code # Code Explanation * First we use `split()` to be able to work on each character as an Array element * Then use `map()` to process each element from binary to decimal using `pareseInt()` * Last we can use `String.fromCharCode()` to convert each ASCII number into the corresponding character * However `fromCharCode()` expects a series of numbers rather than an Array! We can use ES6 Spread Operator to pass in an Array of numbers as individual numbers. See here for more info; Spread Operator ## Relevant Links * Array.prototype.map ## ![:clipboard:](https://forum.freecodecamp.com/images/emoji/emoji_one/clipboard.png?v=3 ":clipboard:") NOTES FOR CONTRIBUTIONS: * ![:warning:](https://forum.freecodecamp.com/images/emoji/emoji_one/warning.png?v=3 ":warning:") **DO NOT** add solutions that are similar to any existing solutions. If you think it is **_similar but better_**, then try to merge (or replace) the existing similar solution. * Add an explanation of your solution. * Categorize the solution in one of the following categories — **Basic**, **Intermediate** and **Advanced**. ![:traffic_light:](https://forum.freecodecamp.com/images/emoji/emoji_one/traffic_light.png?v=3 ":traffic_light:") * Please add your username only if you have added any **relevant main contents**. 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